Hi Reg,
Thanks for the drawings. I was thinking along the lines of your second drawing except the opposite sides of the diodes would be connected to the switches. So basically, instead of the gain for that path being zero(by shorting with the switch), that path is essentially open circuited with a switch instead.
Thanks again,
Brian
Thanks for the drawings. I was thinking along the lines of your second drawing except the opposite sides of the diodes would be connected to the switches. So basically, instead of the gain for that path being zero(by shorting with the switch), that path is essentially open circuited with a switch instead.
Thanks again,
Brian
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