Measured SRF with oscope and probe loop precedure,counts 2.38MHz
Rd=pi*L*SRF --> Rd=3.14 * 0.00032 * 2380000 --> Rd=2391.4 Ohms
Rd*Rd= L / 4*C --> C= L / Rd*Rd*4 --> C= 0.00032 / 2391.4 * 2391.4 *4 --> C = 0.00032/5718794 --> C = 5.59 e-11 --> 55pF
Conclusion:As SRF goes higher the Rd goes higher therefor capacitance goes higher.So we supose to lower the SRF but how???
And my embarassing moment of the day,what do you mean by "lead" ??
Originally posted by green
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Originally posted by green
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Originally posted by green
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Originally posted by green
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