Originally posted by green
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I attach the field calculator link and a screenshot of the coil numbers.
I took the medium diameter of the coil at radius 12.5cm and then the distance of the diameter of the coil, x 2, because the signal emitted from the silver dollar target will have to travel that same distance to the RX coil.
The coil, when taking the reading of about 1.2V, as running at 5A peak TX current.
The coil has 26 turns, therefore we input 5x26=130A.
The coil field strength at the coil center is 6.534G
At a distance of 50cm, the coil field strength is 0.093, or about 70 times less.
Therefore, the signal amplitude from the silver dollar at a distance of 25cm from the coil will be about 120mV/70=1.7mV
Magnetic Field of a Current Loop

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