Originally posted by 1843
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there are other parts connected... like inverting input resistor you didn't draw.
In differential configurations you must mantain simmetry of the two halves to get the differentiation on common mode noise: it's a benefit to you.
So, if you change one , you need to change the other as well.
Both, opening or not the switch, you get a polarization voltage at the lower 120K, thus providing the effect of a battery there used to fix an offset, required for proper operations of preamp far from saturation.
In both cases you actually don't need, to simplify, both resistors to be 120K, they could be also different values. But if the scope is mantaining hi immunity to common mode noise... well... it's strongly suggested you keep them same value there.
This way, the simmetry give you always A(V2-V1), V2 is at + lead, V1 is at - lead and A is the voltage gain...(in your case is 120/1=120 times)... that means a common mode noise will have two amplified components in phase opposition and will be virtually eliminated from signal at output.
This is no matter of which signals you put at inputs, if they are compatible with linear behaviour of the amplifier.
So, though not strictly required for signal amplification it's good you keep simmetry to gain the maximum common mode noise reduction.
Without this your preamp will work too, and you'll not notice big differences there... but cause PIs have enormous amplification along the chain you'll get sooner or later that dang noise propagate being amplified and then create big troubles.
Kind regards,
Max
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