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  • Aziz
    replied
    Hi all,

    I'm very excited about the 2N 3904!

    Total collector current 5.8 mA (seems to be the best value so far). I have added a complementary NPN/PNP BJT driver stage to the output of the op-amp.

    Results:
    4x 2N 3904 + NE5534A (Gain resistors: 470 Ohm, 2.2 Ohm):
    en = 0.376 nV/sqrt(Hz), in = 6.356 pA/sqrt(Hz)

    3x 2N 3904 + NE5534A (Gain resistors: 470 Ohm, 2.2 Ohm):
    en = 0.398 nV/sqrt(Hz), in = 6.505 pA/sqrt(Hz)

    4x 2N 3904 + NE5534A (Gain resistors: 1k Ohm, 2.2 Ohm, more gain):
    en = 0.284 nV/sqrt(Hz), in = 6.051 pA/sqrt(Hz)
    (Cheap trick of course! *LOL*)

    How is that now?


    I'll start the PNP prototype soon. Or investigating another NPN BJT. But the MJE 13007 doesn't like paralleling. I can use only one.
    Cheers,
    ^sif

    Leave a comment:


  • Aziz
    replied
    Originally posted by vbeeeks View Post
    Found one quick reference for noise measurements:
    http://www.4shared.com/office/ZSM__s...Lowest-No.html
    Thanks! I couldn't load it so I have found another source:

    or

    DepositFiles provides you with a legitimate technical solution, which enables you to upload, store, access and download text, software, scripts, images, sounds, videos, animations and any other materials in form of one or several electronic files.


    Aziz

    Leave a comment:


  • vbeeeks
    replied
    Found one quick reference for noise measurements:

    Leave a comment:


  • Aziz
    replied
    Latest Measurements

    Hi all,

    this is the latest measurement list (see below the Excel zip-file). I have to make more measurements with different collector currents yet (only for some interesting BJT's of course).

    AC-Amplifier-Noise-Measurements-04.zip

    See, how a parallel of super cheap 2N 3904's excels.


    Cheers,
    Aziz

    Leave a comment:


  • Aziz
    replied
    Did we "invent" a new measurement method?

    Trivial. I don't think so!
    ^sif

    Leave a comment:


  • Aziz
    replied
    Originally posted by clancy View Post
    Thanks Aziz.
    Actually, these useful measures because it give measurement bandwidth = 85.5Hz. This mean that your measures in #96 (Shorted-Input-0-Ohm-Gain206.gif), preamp noise be 1.3nV/sqrt(Hz) at 1kHz, and 0.94nV/sqrt(Hz) at -115dB.
    Hi Clancy,

    my latest noise floor level decibel measurements were taken from the flat noise region of the frequency spectrum (averaged over 6 kHz to 30 kHz). I don't look at the low frequency region at the moment. The low frequency region noise is larger of course. I'm focussing to the approaching noise density level (best noise figure). In principle, I could measure the whole frequency spectrum from 50 Hz to 48 kHz with FFT-bin size frequency resolution and calculate the noise density for each.
    The flat region is often beginning earlier (>1 kHz). But some transistors/op-amps causing it happen later. I could lower it to 3 kHz but I think, it's not required.
    Cheers,
    Aziz

    Leave a comment:


  • clancy
    replied
    Thanks Aziz.
    Actually, these useful measures because it give measurement bandwidth = 85.5Hz. This mean that your measures in #96 (Shorted-Input-0-Ohm-Gain206.gif), preamp noise be 1.3nV/sqrt(Hz) at 1kHz, and 0.94nV/sqrt(Hz) at -115dB.





    Leave a comment:


  • Aziz
    replied
    Interesting. The 2x 2N 3904 is performing very well for very low source impedances.
    And very cheap (0.04 EUR per BJT).
    Again the poor performance of the BC 550C. Forget it! Throw it out of the window. *LOL*
    Click image for larger version

Name:	BJT+op-amp-noise-in-AC-amp-03.gif
Views:	1
Size:	57.7 KB
ID:	339540

    Cheers,
    ^sif

    Leave a comment:


  • Aziz
    replied
    Hi all,

    I have updated my Excel file and have put a few measurements this morning (see below zip-file). So you can check, whether I have calculated it correctly. I have to check it yet. But these noise figures make more sense now!
    Ok, up that new goal to 0.5 nV/sqrt(Hz). Oh boy!, this is going to be very very difficult now.

    Excel zip-file:
    AC-Amplifier-Noise-Measurements-01.zip

    Cheers,
    Aziz,
    onto way to ultra low noise heaven.

    Leave a comment:


  • Aziz
    replied
    Originally posted by clancy View Post
    BTW, this preamp noise figure poor compared to good low noise opamp because of very high noise current = sqrt([N1(J2^2+V^2)-N2(J1^2+V^2)]/[N2R1^2-N1R2^2]) =7.8pA/sqrt(Hz), V=preamp voltage noise.
    Thanks for providing the current density too. I just saw it. I get the same result.
    Aziz

    Leave a comment:


  • Aziz
    replied
    But this is a very bad news for the 1k series resistor fraction.
    In the example above of in = 7.8 pA/sqrt(Hz):
    in is causing 7.8 pA * 1000 Ohm = 7.8 nV voltage noise. This is all screwing the performance of the ultra-low-noise thing.


    Anyway. I'm looking forward to the new set of more accurate measurements.
    Cheers,
    ^sif

    Leave a comment:


  • Aziz
    replied
    Originally posted by clancy View Post
    Was wondering when you going to thinks you forget current noise.
    J1 = (Johnson noise R1)^2/Hz, J2 = (Johnson noise R2)^2/Hz

    N1= (measured noise R1)^2, N2=( measured noise R2)^2, N0= (measured noise 0 Ohms)^2
    (Amplifier voltage noise at input)/sqrt(Hz) = sqrt{[J1(R2/R1)^2-J2]/[(R2/R1)^2(N1/N0-1)-N2/N0+1]} = 0.65nV/sqrt(Hz). This math independent of gain as should.


    Bravo Clancy,

    I'm very impressed! I get the same voltage noise density en = 0.649 nV/sqrt(Hz). And current density in = 7.835 pA/sqrt(Hz).
    The formulas are somewhat f**kn complex (see below). Anyway. I have to check them once again. But I'm satisfied to get the same voltage density result.

    Who would have thought, that my first simple measurement method would fail so much? The current noise can't be neglected with resistor noise measurements. I'm happy, that we have now a nice & more accurate measurement method.
    Code:
    Excel-Formula for en:
    =WURZEL(_c*_Ri*(_Ri/_Rp - 1) / ((H86*H86-1)*_Ri*_Ri/(_Rp*_Rp) - I86*I86 + 1))*1000000000
    
    Excel Formula for in:
    =WURZEL((J86*J86/1000000000000000000*(H86*H86-1) - _c*_Rp)/(_Rp*_Rp))*1000000000000
    
    WURZEL = sqrt()-function
    c = 4*k*T

    Cheers,
    Aziz
    PS: Congratulations, you have won that great prize!!!

    Leave a comment:


  • clancy
    replied
    BTW, this preamp noise figure poor compared to good low noise opamp because of very high noise current = sqrt([N1(J2^2+V^2)-N2(J1^2+V^2)]/[N2R1^2-N1R2^2]) =7.8pA/sqrt(Hz), V=preamp voltage noise.

    Leave a comment:


  • clancy
    replied
    Was wondering when you going to thinks you forget current noise.
    J1 = (Johnson noise R1)^2/Hz, J2 = (Johnson noise R2)^2/Hz

    N1= (measured noise R1)^2, N2=( measured noise R2)^2, N0= (measured noise 0 Ohms)^2
    (Amplifier voltage noise at input)/sqrt(Hz) = sqrt{[J1(R2/R1)^2-J2]/[(R2/R1)^2(N1/N0-1)-N2/N0+1]} = 0.65nV/sqrt(Hz). This math independent of gain as should.

    Leave a comment:


  • Aziz
    replied
    Anyone got the two equations?
    Nobody?

    Ok, another trick:
    No one can calculate it! No one!
    Got motivated now?

    Comeon guys, bite the bullet please.
    ^sif

    Leave a comment:

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