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  • green
    replied
    Originally posted by mickstv View Post
    Hi Green the single ended integrator is a smoother than the diff one. The target delay is about 8us.
    Thanks

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  • mickstv
    replied
    Originally posted by green View Post
    When you wave the magnet over the coil do you see a difference between the two integrators when looking at the LPF output with a scope? For me the single input integrator looked a lot better. What is your target delay time?

    Hi Green the single ended integrator is a smoother than the diff one. The target delay is about 8us.

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  • green
    replied
    Originally posted by mickstv View Post
    I have two detectors both PI GB one is using a single input integrator and the other is using a differential integrator, both circuits needed a small value multiturn pot to smooth out EF.

    My target sample is 5us and GB is 130us minus EF 125us. These wide samples cause ripple on the output of both integrator types especially when a magnet of magnetic soil is waved over the coil, so I added a 2 pole LPF filter to the outputs of both integrators to smooth the output.

    Final note the GB point between both integrator types is different. The differential integrator one has a GB delay from target sample of 18us, whereas the single input integrator has a GB delay of about 27us.
    When you wave the magnet over the coil do you see a difference between the two integrators when looking at the LPF output with a scope? For me the single input integrator looked a lot better. What is your target delay time?

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  • mickstv
    replied
    Originally posted by green View Post
    The single input integrator #2 works with one or two input resistors. The first time I had one. When I rebuilt it after trying the differential integrator I left the other one in the circuit for two input resistors. All 1% metal film resistors. Needed to add a offset trim pot to the preamp to minimize the integrator output ripple.


    Target and EF sample 10usec, GEB and EF sample 100usec. The differential sampling integrator #1 has the same problem with just the target and EF sample or all four samples.


    I have two detectors both PI GB one is using a single input integrator and the other is using a differential integrator, both circuits needed a small value multiturn pot to smooth out EF.

    My target sample is 5us and GB is 130us minus EF 125us. These wide samples cause ripple on the output of both integrator types especially when a magnet of magnetic soil is waved over the coil, so I added a 2 pole LPF filter to the outputs of both integrators to smooth the output.

    Final note the GB point between both integrator types is different. The differential integrator one has a GB delay from target sample of 18us, whereas the single input integrator has a GB delay of about 27us.

    Leave a comment:


  • Orbit
    replied
    Should be a beautiful works !

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  • green
    replied
    Originally posted by Teleno View Post
    I was referring fo #1 in Eric's image. Now I see it's #2 in your image and there's an inverting bufer.

    in circuit #1 the output is the integral of the diference in the input currents (see here). Assuming both samples have the same amplitude V, the current at the non-inverting input is V/3K because the resistor is connected to virtual ground. However, the current at the non-inverting input is not V/3K because the other end of the resistor is connected to a floating potential that depends on the level of charge of the lower capacitor. That's why you can't achieve voltage cancelling.

    The botton line: #1 is a current differential integrator suited for current sources, while #2 is a voltage diferential integrator. You should stick to #2 because your signal is voltage.
    I don't use either arrangement now as matching the two sets of RC components was always a pain and you get a far better performance by summing + and - signals into a single TC integrator. More on that later.

    Eric.

    I agree. Eric's statement says the same.

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  • Carl-NC
    replied
    A small-signal AC analysis suggests both opamp approaches should give the same results, but because they are used in a large-signal voltage sampling application they do not. Teleno got it right, it's the voltage sampling on the non-inverting side that screws up #1. I use option #2 (or variations of it) because it is a true integrator for both polarities, does a better job of reducing thermal and flicker noise, has better EF rejection, and doesn't require cap matching (unless you have a ground channel). The only downside is the extra opamp for signal inversion.

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  • Teleno
    replied
    Originally posted by green View Post
    The target sample goes to the inverting input switch. The EF sample goes to the non inverting input switch. Preamp out, no inverter. You need an inverter for the single input integrator #2.
    I was referring to #1 in Eric's image. Now I see it's #2 in your image and there's an inverting buffer.

    in circuit #1 the output is the integral of the diference in the input currents (see here). Assuming both samples have the same amplitude V, the current at the non-inverting input is V/3K because the resistor is connected to virtual ground. However, the current at the non-inverting input is not V/3K because the other end of the resistor is connected to a floating potential that depends on the level of charge of the lower capacitor. That's why you can't achieve voltage cancelling.

    The botton line: #1 is a current differential integrator suited for current sources, while #2 is a voltage diferential integrator. You should stick to #2 because your signal is voltage.

    Leave a comment:


  • Orbit
    replied
    For some reason below integrator works well but creates quite noise I write from experience !

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  • green
    replied
    Originally posted by Teleno View Post
    If you use integrator #1 you must invert the second sample before feeding it to the integrator or else the samples won't subtract. Are you doing that?
    The target sample goes to the inverting input switch. The EF sample goes to the non inverting input switch. Preamp out, no inverter. You need an inverter for the single input integrator #2.

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  • Teleno
    replied
    If you use integrator #1 you must invert the second sample before feeding it to the integrator or else the samples won't subtract. Are you doing that?

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  • green
    replied
    Originally posted by ODM View Post
    You could use just one input resistor in the single input integrator. Are they matched?

    One thing may be uneven gain recovery after opamp overload, even if a scope plot shows steady decay, HF gain may not have recovered yet. This can be seen when step driving an opamp into overload with a small HF signal riding on top, the HF gain recovers slower than bias point in some opamps. - Does it get better if you increase target sample delay?

    When having more than one integrator in the design it starts paying off to make them single input versions, as they take up less board space especially in SMD and matching channels needs half the matched capacitors.
    Charge injection is different on the dual input one, as its input are resistive and the single version is virtual ground, but in practice the difference is minimal.
    The single input integrator #2 works with one or two input resistors. The first time I had one. When I rebuilt it after trying the differential integrator I left the other one in the circuit for two input resistors. All 1% metal film resistors. Needed to add a offset trim pot to the preamp to minimize the integrator output ripple.


    Target and EF sample 10usec, GEB and EF sample 100usec. The differential sampling integrator #1 has the same problem with just the target and EF sample or all four samples.


    The differential input integrator is simpler. Add one resistor and capacitor. The resistors and capacitors were matched. Have to add an op amp and some resistors for the inverter to the single input integrator. The problem is I can't get the differential input integrator to work as good as the single input integrator.

    Leave a comment:


  • green
    replied
    Originally posted by 6666 View Post
    Is it a metallic magnet ?
    No. The #2 integrator does a good job of reducing the magnet signal.

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  • ODM
    replied
    You could use just one input resistor in the single input integrator. Are they matched?

    One thing may be uneven gain recovery after opamp overload, even if a scope plot shows steady decay, HF gain may not have recovered yet. This can be seen when step driving an opamp into overload with a small HF signal riding on top, the HF gain recovers slower than bias point in some opamps. - Does it get better if you increase target sample delay?

    When having more than one integrator in the design it starts paying off to make them single input versions, as they take up less board space especially in SMD and matching channels needs half the matched capacitors.
    Charge injection is different on the dual input one, as its input are resistive and the single version is virtual ground, but in practice the difference is minimal.

    Leave a comment:


  • 6666
    replied
    Originally posted by green View Post
    http://www.geotech1.com/forums/showt...421#post171421
    Might be the reason I've been using the #2 integrator. He didn't get to (more on that latter). Reply #1 is the same as your image.


    Was trying to calculate gain and frequency response for the track and hold integrator. Not sure the calculations are correct. I've been trying to add GEB and I think changing sample time doesn't change gain so I think track-hold integrator is not a good choice.

    Some of the PI's use integrator #1. Matching caps and resistors wasn't a problem. I still don't see why it doesn't cancel the magnet better.

    Is it a metallic magnet ?

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