Wrong way to look at it. The short pulse is roughly a square wave. The capacitor provides a kick-start voltage to rapidly get the coil current up to 5 amps, after that the 5V supply (via D1) powers the coil. The energy in the cap is 0.5*C*V2 and the (same) energy transferred to the coil is 0.5*L*I2. So you have
0.5*C*V2 = 0.5*L*I2
I2 = V2*C/L
I don't recall the inductance but let's say it's 300uH. The boost current is
I = V*sqrt(C/L) = 175*sqrt(56nF/300uH)
I = 2.4A
This charges the coil as far as it can, then the 5V takes over.
0.5*C*V2 = 0.5*L*I2
I2 = V2*C/L
I don't recall the inductance but let's say it's 300uH. The boost current is
I = V*sqrt(C/L) = 175*sqrt(56nF/300uH)
I = 2.4A
This charges the coil as far as it can, then the 5V takes over.

Comment