Originally posted by ivconic
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the positive voltage drop is not good stuff... and have nothing to do with voltage converter unless there's some strange error on transistors there...make another test too...
TRY THIS:
disconnect output pin of 8V regulator and look for current drawn by device... connect amp-meter before give power to device... better if analog kind of meter there... and look how much current drain there is and how behave startup of device (initial peak ? etc).
Then post here informations:
look ! if your regulator , 7808 (right ?) , have 2 volts drop there you maybe probably have bad supply (too low I mean ...not 12V) or you have something that drain too much current on circuit... but really much current ! 7808 is rated 1ampere ...and I think can't be this way cause with so hi current you'll have regulator running really hot and some part in the circuit burns... etc
Maybe your powersupply doesn't give enough real "voltage" to 7808 to work properly ? You need at least 11volts there... otherwise you cannot have real 8V at output under real conditions of load.
If you test with batteries be sure they are charged well and don't drop under 11volts during operations...otherwise you know what will happen... your regulated voltage will drop too really easy under 8volts cause of internal dropout.
Kind regards,
Max





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